Base | Representation |
---|---|
bin | 100101010001101011… |
… | …101001010001111001 |
3 | 10211022102021211012012 |
4 | 211101223221101321 |
5 | 1123432411221213 |
6 | 30215352455305 |
7 | 2614600514552 |
oct | 452153512171 |
9 | 124272254165 |
10 | 40025101433 |
11 | 15a7a143129 |
12 | 79103aa535 |
13 | 3a0b330995 |
14 | 1d19a63329 |
15 | 1093ce44a8 |
hex | 951ae9479 |
40025101433 has 24 divisors (see below), whose sum is σ = 41388303360. Its totient is φ = 38700396000.
The previous prime is 40025101421. The next prime is 40025101451. The reversal of 40025101433 is 33410152004.
40025101433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 40025101433 - 212 = 40025097337 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 40025101399 and 40025101408.
It is not an unprimeable number, because it can be changed into a prime (40025101933) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 64660598 + ... + 64661216.
It is an arithmetic number, because the mean of its divisors is an integer number (1724512640).
Almost surely, 240025101433 is an apocalyptic number.
It is an amenable number.
40025101433 is a deficient number, since it is larger than the sum of its proper divisors (1363201927).
40025101433 is a wasteful number, since it uses less digits than its factorization.
40025101433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 989 (or 918 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 40025101433 its reverse (33410152004), we get a palindrome (73435253437).
The spelling of 40025101433 in words is "forty billion, twenty-five million, one hundred one thousand, four hundred thirty-three".
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