Base | Representation |
---|---|
bin | 111010010110101101111… |
… | …101001111100101000011 |
3 | 112012100211100220101111221 |
4 | 322112231331033211003 |
5 | 1011200212442001011 |
6 | 12310120341015511 |
7 | 562502405043043 |
oct | 72265575174503 |
9 | 15170740811457 |
10 | 4010123000131 |
11 | 1306757987486 |
12 | 5492320b4597 |
13 | 2311cb120541 |
14 | dc13b95d723 |
15 | 6e4a4a62971 |
hex | 3a5adf4f943 |
4010123000131 has 8 divisors (see below), whose sum is σ = 4246030908000. Its totient is φ = 3774217127808.
The previous prime is 4010123000129. The next prime is 4010123000239. The reversal of 4010123000131 is 1310003210104.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4010123000131 - 21 = 4010123000129 is a prime.
It is a super-2 number, since 2×40101230001312 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4010123000101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5738605 + ... + 6399361.
It is an arithmetic number, because the mean of its divisors is an integer number (530753863500).
Almost surely, 24010123000131 is an apocalyptic number.
4010123000131 is a deficient number, since it is larger than the sum of its proper divisors (235907907869).
4010123000131 is a wasteful number, since it uses less digits than its factorization.
4010123000131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1017773.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 4010123000131 its reverse (1310003210104), we get a palindrome (5320126210235).
The spelling of 4010123000131 in words is "four trillion, ten billion, one hundred twenty-three million, one hundred thirty-one", and thus it is an aban number.
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