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4010123000129 is a prime number
BaseRepresentation
bin111010010110101101111…
…101001111100101000001
3112012100211100220101111212
4322112231331033211001
51011200212442001004
612310120341015505
7562502405043041
oct72265575174501
915170740811455
104010123000129
111306757987484
125492320b4595
132311cb12053c
14dc13b95d721
156e4a4a6296e
hex3a5adf4f941

4010123000129 has 2 divisors, whose sum is σ = 4010123000130. Its totient is φ = 4010123000128.

The previous prime is 4010123000113. The next prime is 4010123000239. The reversal of 4010123000129 is 9210003210104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3984523000129 + 25600000000 = 1996127^2 + 160000^2 .

It is a cyclic number.

It is not a de Polignac number, because 4010123000129 - 24 = 4010123000113 is a prime.

It is a super-3 number, since 3×40101230001293 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (4010123000329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005061500064 + 2005061500065.

It is an arithmetic number, because the mean of its divisors is an integer number (2005061500065).

Almost surely, 24010123000129 is an apocalyptic number.

It is an amenable number.

4010123000129 is a deficient number, since it is larger than the sum of its proper divisors (1).

4010123000129 is an equidigital number, since it uses as much as digits as its factorization.

4010123000129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

The spelling of 4010123000129 in words is "four trillion, ten billion, one hundred twenty-three million, one hundred twenty-nine", and thus it is an aban number.