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401104035403 = 431930635813
BaseRepresentation
bin1011101011000111010…
…10011101111001001011
31102100022122000011211221
411311203222131321023
523032430113113103
6504133055302511
740656506022061
oct5654352357113
91370278004757
10401104035403
1114511a853555
12658a0b1aa37
132ba932a2a26
14155b0a72031
15a6787ca1bd
hex5d63a9de4b

401104035403 has 4 divisors (see below), whose sum is σ = 402034671648. Its totient is φ = 400173399160.

The previous prime is 401104035349. The next prime is 401104035413. The reversal of 401104035403 is 304530401104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 401104035403 - 225 = 401070480971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (401104035413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 465317476 + ... + 465318337.

It is an arithmetic number, because the mean of its divisors is an integer number (100508667912).

Almost surely, 2401104035403 is an apocalyptic number.

401104035403 is a deficient number, since it is larger than the sum of its proper divisors (930636245).

401104035403 is an equidigital number, since it uses as much as digits as its factorization.

401104035403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 930636244.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 401104035403 its reverse (304530401104), we get a palindrome (705634436507).

The spelling of 401104035403 in words is "four hundred one billion, one hundred four million, thirty-five thousand, four hundred three".

Divisors: 1 431 930635813 401104035403