Base | Representation |
---|---|
bin | 10010001111010111101000… |
… | …10010001010000010010011 |
3 | 12021000112012220211120022021 |
4 | 21013223310102022002103 |
5 | 20224132302232313301 |
6 | 221150302151152311 |
7 | 11306613441116656 |
oct | 1107536422120223 |
9 | 167015186746267 |
10 | 40110503010451 |
11 | 118648502a83a5 |
12 | 45b9826375697 |
13 | 194c534061a93 |
14 | 9c95043d989d |
15 | 4985760748a1 |
hex | 247af448a093 |
40110503010451 has 4 divisors (see below), whose sum is σ = 40216335472600. Its totient is φ = 40004670548304.
The previous prime is 40110503010407. The next prime is 40110503010491. The reversal of 40110503010451 is 15401030501104.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 40110503010451 - 217 = 40110502879379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40110503010491) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52916230506 + ... + 52916231263.
It is an arithmetic number, because the mean of its divisors is an integer number (10054083868150).
Almost surely, 240110503010451 is an apocalyptic number.
40110503010451 is a deficient number, since it is larger than the sum of its proper divisors (105832462149).
40110503010451 is a wasteful number, since it uses less digits than its factorization.
40110503010451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 105832462148.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 40110503010451 its reverse (15401030501104), we get a palindrome (55511533511555).
The spelling of 40110503010451 in words is "forty trillion, one hundred ten billion, five hundred three million, ten thousand, four hundred fifty-one".
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