Base | Representation |
---|---|
bin | 111010010111101010101… |
… | …001110010011111000011 |
3 | 112012110110100000220121012 |
4 | 322113222221302133003 |
5 | 1011204304133413103 |
6 | 12310405354551135 |
7 | 562536551404463 |
oct | 72275251623703 |
9 | 15173410026535 |
10 | 4011141310403 |
11 | 130712a777017 |
12 | 5494771384ab |
13 | 23133109b9b6 |
14 | dc1d6cb5ba3 |
15 | 6e51415e2d8 |
hex | 3a5eaa727c3 |
4011141310403 has 4 divisors (see below), whose sum is σ = 4031297799600. Its totient is φ = 3990984821208.
The previous prime is 4011141310327. The next prime is 4011141310441. The reversal of 4011141310403 is 3040131411104.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4011141310403 - 28 = 4011141310147 is a prime.
It is a super-2 number, since 2×40111413104032 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4011141315403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10078244300 + ... + 10078244697.
It is an arithmetic number, because the mean of its divisors is an integer number (1007824449900).
Almost surely, 24011141310403 is an apocalyptic number.
4011141310403 is a deficient number, since it is larger than the sum of its proper divisors (20156489197).
4011141310403 is a wasteful number, since it uses less digits than its factorization.
4011141310403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20156489196.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 4011141310403 its reverse (3040131411104), we get a palindrome (7051272721507).
The spelling of 4011141310403 in words is "four trillion, eleven billion, one hundred forty-one million, three hundred ten thousand, four hundred three".
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