Base | Representation |
---|---|
bin | 10010001111011001100011… |
… | …10110101110100011101001 |
3 | 12021000121212220121020201120 |
4 | 21013230301312232203221 |
5 | 20224141411204214101 |
6 | 221150552452005453 |
7 | 11306651153340615 |
oct | 1107546166564351 |
9 | 167017786536646 |
10 | 40111536007401 |
11 | 11865230409291 |
12 | 45b9a74300889 |
13 | 194c66a083091 |
14 | 9c95a1696345 |
15 | 4985d6ac2b36 |
hex | 247b31dae8e9 |
40111536007401 has 64 divisors (see below), whose sum is σ = 54776641305600. Its totient is φ = 26103368318976.
The previous prime is 40111536007397. The next prime is 40111536007427. The reversal of 40111536007401 is 10470063511104.
It is not a de Polignac number, because 40111536007401 - 22 = 40111536007397 is a prime.
It is a super-3 number, since 3×401115360074013 (a number of 42 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (40111536006401) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 11752572571 + ... + 11752575983.
It is an arithmetic number, because the mean of its divisors is an integer number (855885020400).
Almost surely, 240111536007401 is an apocalyptic number.
It is an amenable number.
40111536007401 is a deficient number, since it is larger than the sum of its proper divisors (14665105298199).
40111536007401 is a wasteful number, since it uses less digits than its factorization.
40111536007401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5138.
The product of its (nonzero) digits is 10080, while the sum is 33.
Adding to 40111536007401 its reverse (10470063511104), we get a palindrome (50581599518505).
The spelling of 40111536007401 in words is "forty trillion, one hundred eleven billion, five hundred thirty-six million, seven thousand, four hundred one".
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