Base | Representation |
---|---|
bin | 10010001111011100100010… |
… | …00011111011101001010011 |
3 | 12021000210000020012100021210 |
4 | 21013232101003323221103 |
5 | 20224203144111220103 |
6 | 221151415151351203 |
7 | 11310035560212315 |
oct | 1107562103735123 |
9 | 167023006170253 |
10 | 40113133304403 |
11 | 11865980004155 |
12 | 45ba23b222503 |
13 | 194c862c80733 |
14 | 9c96b38857b5 |
15 | 49867be3ae03 |
hex | 247b910fba53 |
40113133304403 has 8 divisors (see below), whose sum is σ = 56299134462400. Its totient is φ = 25334610508008.
The previous prime is 40113133304401. The next prime is 40113133304443. The reversal of 40113133304403 is 30440333131104.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 40113133304403 - 21 = 40113133304401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40113133304401) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 351869590333 + ... + 351869590446.
It is an arithmetic number, because the mean of its divisors is an integer number (7037391807800).
Almost surely, 240113133304403 is an apocalyptic number.
40113133304403 is a deficient number, since it is larger than the sum of its proper divisors (16186001157997).
40113133304403 is a wasteful number, since it uses less digits than its factorization.
40113133304403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 703739180801.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 40113133304403 its reverse (30440333131104), we get a palindrome (70553466435507).
The spelling of 40113133304403 in words is "forty trillion, one hundred thirteen billion, one hundred thirty-three million, three hundred four thousand, four hundred three".
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