40113230433 has 4 divisors (see below), whose sum is σ = 53484307248. Its totient is φ = 26742153620.

The previous prime is 40113230429. The next prime is 40113230449. The reversal of 40113230433 is 33403231104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40113230433 - 2² = 40113230429 is a prime.

It is not an unprimeable number, because it can be changed into a prime (40113230453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6685538403 + ... + 6685538408.

It is an arithmetic number, because the mean of its divisors is an integer number (13371076812).

Almost surely, 2^40113230433 is an apocalyptic number.

It is an amenable number.

40113230433 is a deficient number, since it is larger than the sum of its proper divisors (13371076815).

40113230433 is a wasteful number, since it uses less digits than its factorization.

40113230433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13371076814.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 40113230433 its reverse (33403231104), we get a palindrome (73516461537).

The spelling of 40113230433 in words is "forty billion, one hundred thirteen million, two hundred thirty thousand, four hundred thirty-three".