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40113431103 = 313371143701
BaseRepresentation
bin100101010110111100…
…100110001000111111
310211112120111102201110
4211112330212020333
51124123014243403
630232230013103
72620022352504
oct452674461077
9124476442643
1040113431103
1116014a93559
127935aa7193
133a23719565
141d276974ab
15109b941103
hex956f2623f

40113431103 has 4 divisors (see below), whose sum is σ = 53484574808. Its totient is φ = 26742287400.

The previous prime is 40113431087. The next prime is 40113431147. The reversal of 40113431103 is 30113431104.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 40113431103 - 24 = 40113431087 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 40113431103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40113031103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6685571848 + ... + 6685571853.

It is an arithmetic number, because the mean of its divisors is an integer number (13371143702).

Almost surely, 240113431103 is an apocalyptic number.

40113431103 is a deficient number, since it is larger than the sum of its proper divisors (13371143705).

40113431103 is a wasteful number, since it uses less digits than its factorization.

40113431103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13371143704.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 40113431103 its reverse (30113431104), we get a palindrome (70226862207).

Subtracting from 40113431103 its reverse (30113431104), we obtain a palindrome (9999999999).

The spelling of 40113431103 in words is "forty billion, one hundred thirteen million, four hundred thirty-one thousand, one hundred three".

Divisors: 1 3 13371143701 40113431103