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4011401113311 = 323193301224083
BaseRepresentation
bin111010010111111010001…
…000110110111011011111
3112012111010102220021012010
4322113322020312323133
51011210322141111221
612310451235242303
7562546154605404
oct72277210667337
915174112807163
104011401113311
111307253395869
1254952a149393
13231372b64327
14dc21d5c42ab
156e52bd7cc76
hex3a5fa236edf

4011401113311 has 16 divisors (see below), whose sum is σ = 5609997340416. Its totient is φ = 2544741044736.

The previous prime is 4011401113283. The next prime is 4011401113333. The reversal of 4011401113311 is 1133111041104.

It is not a de Polignac number, because 4011401113311 - 215 = 4011401080543 is a prime.

It is a super-2 number, since 2×40114011133112 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4011401113351) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 150598725 + ... + 150625358.

It is an arithmetic number, because the mean of its divisors is an integer number (350624833776).

Almost surely, 24011401113311 is an apocalyptic number.

4011401113311 is a deficient number, since it is larger than the sum of its proper divisors (1598596227105).

4011401113311 is a wasteful number, since it uses less digits than its factorization.

4011401113311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 301224302.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 4011401113311 its reverse (1133111041104), we get a palindrome (5144512154415).

The spelling of 4011401113311 in words is "four trillion, eleven billion, four hundred one million, one hundred thirteen thousand, three hundred eleven".

Divisors: 1 3 23 69 193 579 4439 13317 301224083 903672249 6928153909 20784461727 58136248019 174408744057 1337133704437 4011401113311