Base | Representation |
---|---|
bin | 111010011000100101001… |
… | …011110111111011110001 |
3 | 112012112222202212101012112 |
4 | 322120211023313323301 |
5 | 1011213312032333040 |
6 | 12311051034535105 |
7 | 562603104364346 |
oct | 72304513677361 |
9 | 15175882771175 |
10 | 4012123324145 |
11 | 1307594025522 |
12 | 5496abb97495 |
13 | 23145967c211 |
14 | dc28b4a07cd |
15 | 6e57048b365 |
hex | 3a6252f7ef1 |
4012123324145 has 4 divisors (see below), whose sum is σ = 4814547988980. Its totient is φ = 3209698659312.
The previous prime is 4012123324043. The next prime is 4012123324151. The reversal of 4012123324145 is 5414233212104.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 629058369424 + 3383064954721 = 793132^2 + 1839311^2 .
It is a cyclic number.
It is not a de Polignac number, because 4012123324145 - 218 = 4012123062001 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 401212332410 + ... + 401212332419.
It is an arithmetic number, because the mean of its divisors is an integer number (1203636997245).
Almost surely, 24012123324145 is an apocalyptic number.
It is an amenable number.
4012123324145 is a deficient number, since it is larger than the sum of its proper divisors (802424664835).
4012123324145 is an equidigital number, since it uses as much as digits as its factorization.
4012123324145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 802424664834.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 4012123324145 its reverse (5414233212104), we get a palindrome (9426356536249).
The spelling of 4012123324145 in words is "four trillion, twelve billion, one hundred twenty-three million, three hundred twenty-four thousand, one hundred forty-five".
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