Base | Representation |
---|---|
bin | 111010011000100101100… |
… | …110100010000100000111 |
3 | 112012120000021000102100211 |
4 | 322120211212202010013 |
5 | 1011213320324444310 |
6 | 12311051444420251 |
7 | 562603220651416 |
oct | 72304546420407 |
9 | 15176007012324 |
10 | 4012130312455 |
11 | 1307597a68991 |
12 | 5496b23a7687 |
13 | 23145ac58005 |
14 | dc28c39d47d |
15 | 6e570dbbc8a |
hex | 3a6259a2107 |
4012130312455 has 4 divisors (see below), whose sum is σ = 4814556374952. Its totient is φ = 3209704249960.
The previous prime is 4012130312419. The next prime is 4012130312461. The reversal of 4012130312455 is 5542130312104.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 4012130312455 - 211 = 4012130310407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 401213031241 + ... + 401213031250.
It is an arithmetic number, because the mean of its divisors is an integer number (1203639093738).
Almost surely, 24012130312455 is an apocalyptic number.
4012130312455 is a deficient number, since it is larger than the sum of its proper divisors (802426062497).
4012130312455 is an equidigital number, since it uses as much as digits as its factorization.
4012130312455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 802426062496.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 4012130312455 its reverse (5542130312104), we get a palindrome (9554260624559).
The spelling of 4012130312455 in words is "four trillion, twelve billion, one hundred thirty million, three hundred twelve thousand, four hundred fifty-five".
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