4012131121003 has 4 divisors (see below), whose sum is σ = 4012191142960. Its totient is φ = 4012071099048.

The previous prime is 4012131120997. The next prime is 4012131121049. The reversal of 4012131121003 is 3001211312104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4012131121003 - 2¹³ = 4012131112811 is a prime.

It is a super-2 number, since 2×4012131121003² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4012131121303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29910600 + ... + 30044437.

It is an arithmetic number, because the mean of its divisors is an integer number (1003047785740).

Almost surely, 2^{4012131121003} is an apocalyptic number.

4012131121003 is a deficient number, since it is larger than the sum of its proper divisors (60021957).

4012131121003 is an equidigital number, since it uses as much as digits as its factorization.

4012131121003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60021956.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 4012131121003 its reverse (3001211312104), we get a palindrome (7013342433107).

The spelling of 4012131121003 in words is "four trillion, twelve billion, one hundred thirty-one million, one hundred twenty-one thousand, three".