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4012131121049 is a prime number
BaseRepresentation
bin111010011000100101101…
…001100111011110011001
3112012120000022112111112202
4322120211221213132121
51011213321031333144
612311051514015545
7562603230560012
oct72304551473631
915176008474482
104012131121049
111307598470447
125496b27175b5
1323145b17c07c
14dc28c530009
156e570ecb64e
hex3a625a67799

4012131121049 has 2 divisors, whose sum is σ = 4012131121050. Its totient is φ = 4012131121048.

The previous prime is 4012131120997. The next prime is 4012131121109. The reversal of 4012131121049 is 9401211312104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3810850579600 + 201280541449 = 1952140^2 + 448643^2 .

It is a cyclic number.

It is not a de Polignac number, because 4012131121049 - 28 = 4012131120793 is a prime.

It is a super-2 number, since 2×40121311210492 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4012131121249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006065560524 + 2006065560525.

It is an arithmetic number, because the mean of its divisors is an integer number (2006065560525).

Almost surely, 24012131121049 is an apocalyptic number.

It is an amenable number.

4012131121049 is a deficient number, since it is larger than the sum of its proper divisors (1).

4012131121049 is an equidigital number, since it uses as much as digits as its factorization.

4012131121049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 29.

The spelling of 4012131121049 in words is "four trillion, twelve billion, one hundred thirty-one million, one hundred twenty-one thousand, forty-nine".