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401213230133 = 2111901484503
BaseRepresentation
bin1011101011010100010…
…11000000110000110101
31102100121020110211212012
411311222023000300311
523033141041331013
6504151555534005
740662303121052
oct5655213006065
91370536424765
10401213230133
11145176455131
12659115ba305
132baacab56b1
14155c1378029
15a6831991a8
hex5d6a2c0c35

401213230133 has 4 divisors (see below), whose sum is σ = 403114714848. Its totient is φ = 399311745420.

The previous prime is 401213230129. The next prime is 401213230151. The reversal of 401213230133 is 331032312104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 401213230133 - 22 = 401213230129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 401213230099 and 401213230108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (401213230163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 950742041 + ... + 950742462.

It is an arithmetic number, because the mean of its divisors is an integer number (100778678712).

Almost surely, 2401213230133 is an apocalyptic number.

It is an amenable number.

401213230133 is a deficient number, since it is larger than the sum of its proper divisors (1901484715).

401213230133 is a wasteful number, since it uses less digits than its factorization.

401213230133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1901484714.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 401213230133 its reverse (331032312104), we get a palindrome (732245542237).

The spelling of 401213230133 in words is "four hundred one billion, two hundred thirteen million, two hundred thirty thousand, one hundred thirty-three".

Divisors: 1 211 1901484503 401213230133