4012143141035 has 4 divisors (see below), whose sum is σ = 4814571769248. Its totient is φ = 3209714512824.

The previous prime is 4012143140953. The next prime is 4012143141047. The reversal of 4012143141035 is 5301413412104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4012143141035 - 2²² = 4012138946731 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4012143140989 and 4012143141007.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 401214314099 + ... + 401214314108.

It is an arithmetic number, because the mean of its divisors is an integer number (1203642942312).

Almost surely, 2^{4012143141035} is an apocalyptic number.

4012143141035 is a deficient number, since it is larger than the sum of its proper divisors (802428628213).

4012143141035 is an equidigital number, since it uses as much as digits as its factorization.

4012143141035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 802428628212.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 4012143141035 its reverse (5301413412104), we get a palindrome (9313556553139).

The spelling of 4012143141035 in words is "four trillion, twelve billion, one hundred forty-three million, one hundred forty-one thousand, thirty-five".