Base | Representation |
---|---|
bin | 111010011000100110010… |
… | …111011110000001011001 |
3 | 112012120001011011011202101 |
4 | 322120212113132001121 |
5 | 1011213332121002303 |
6 | 12311053023403401 |
7 | 562603435001323 |
oct | 72304627360131 |
9 | 15176034134671 |
10 | 4012143140953 |
11 | 13075a4230152 |
12 | 5496b6753561 |
13 | 2314607ca13c |
14 | dc28dd7c613 |
15 | 6e5720a2d1d |
hex | 3a6265de059 |
4012143140953 has 2 divisors, whose sum is σ = 4012143140954. Its totient is φ = 4012143140952.
The previous prime is 4012143140899. The next prime is 4012143141047. The reversal of 4012143140953 is 3590413412104.
4012143140953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3688231907529 + 323911233424 = 1920477^2 + 569132^2 .
It is a cyclic number.
It is not a de Polignac number, because 4012143140953 - 229 = 4011606270041 is a prime.
It is not a weakly prime, because it can be changed into another prime (4012143140353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006071570476 + 2006071570477.
It is an arithmetic number, because the mean of its divisors is an integer number (2006071570477).
Almost surely, 24012143140953 is an apocalyptic number.
It is an amenable number.
4012143140953 is a deficient number, since it is larger than the sum of its proper divisors (1).
4012143140953 is an equidigital number, since it uses as much as digits as its factorization.
4012143140953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 4012143140953 in words is "four trillion, twelve billion, one hundred forty-three million, one hundred forty thousand, nine hundred fifty-three".
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