4012164733 has 4 divisors (see below), whose sum is σ = 4012307740. Its totient is φ = 4012021728.

The previous prime is 4012164727. The next prime is 4012164749. The reversal of 4012164733 is 3374612104.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2836840644 + 1175324089 = 53262^2 + 34283^2 .

It is a cyclic number.

It is not a de Polignac number, because 4012164733 - 2¹³ = 4012156541 is a prime.

It is a super-2 number, since 2×4012164733² = 32194931689457922578, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4012164695 and 4012164704.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4012164133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14010 + ... + 90667.

It is an arithmetic number, because the mean of its divisors is an integer number (1003076935).

Almost surely, 2^4012164733 is an apocalyptic number.

It is an amenable number.

4012164733 is a deficient number, since it is larger than the sum of its proper divisors (143007).

4012164733 is a wasteful number, since it uses less digits than its factorization.

4012164733 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 143006.

The product of its (nonzero) digits is 12096, while the sum is 31.

The square root of 4012164733 is about 63341.6508547101. The cubic root of 4012164733 is about 1589.0086159324.

Adding to 4012164733 its reverse (3374612104), we get a palindrome (7386776837).

The spelling of 4012164733 in words is "four billion, twelve million, one hundred sixty-four thousand, seven hundred thirty-three".