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40122042013 = 79515046163
BaseRepresentation
bin100101010111011101…
…011100011010011101
310211120011200220200001
4211113131130122131
51124132220321023
630233134334301
72620155505264
oct452735343235
9124504626601
1040122042013
1116019935009
12793895a391
133a25442a81
141d288995db
15109c5926ad
hex95775c69d

40122042013 has 4 divisors (see below), whose sum is σ = 40127096128. Its totient is φ = 40116987900.

The previous prime is 40122042001. The next prime is 40122042017. The reversal of 40122042013 is 31024022104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40122042013 - 221 = 40119944861 is a prime.

It is a super-4 number, since 4×401220420134 (a number of 44 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40122042017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2515131 + ... + 2531032.

It is an arithmetic number, because the mean of its divisors is an integer number (10031774032).

Almost surely, 240122042013 is an apocalyptic number.

It is an amenable number.

40122042013 is a deficient number, since it is larger than the sum of its proper divisors (5054115).

40122042013 is an equidigital number, since it uses as much as digits as its factorization.

40122042013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5054114.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 40122042013 its reverse (31024022104), we get a palindrome (71146064117).

The spelling of 40122042013 in words is "forty billion, one hundred twenty-two million, forty-two thousand, thirteen".

Divisors: 1 7951 5046163 40122042013