Base | Representation |
---|---|
bin | 111010011000101011100… |
… | …100000010011110110111 |
3 | 112012120021020012102210212 |
4 | 322120223210002132313 |
5 | 1011214021430301403 |
6 | 12311105420140035 |
7 | 562605544013633 |
oct | 72305344023667 |
9 | 15176236172725 |
10 | 4012230322103 |
11 | 1307639466693 |
12 | 54971b99761b |
13 | 2314758a3013 |
14 | dc29b793dc3 |
15 | 6e579a744d8 |
hex | 3a62b9027b7 |
4012230322103 has 4 divisors (see below), whose sum is σ = 4248243870480. Its totient is φ = 3776216773728.
The previous prime is 4012230322049. The next prime is 4012230322127. The reversal of 4012230322103 is 3012230322104.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4012230322103 - 212 = 4012230318007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4012530322103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118006774163 + ... + 118006774196.
It is an arithmetic number, because the mean of its divisors is an integer number (1062060967620).
Almost surely, 24012230322103 is an apocalyptic number.
4012230322103 is a deficient number, since it is larger than the sum of its proper divisors (236013548377).
4012230322103 is a wasteful number, since it uses less digits than its factorization.
4012230322103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 236013548376.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 4012230322103 its reverse (3012230322104), we get a palindrome (7024460644207).
Subtracting from 4012230322103 its reverse (3012230322104), we obtain a palindrome (999999999999).
The spelling of 4012230322103 in words is "four trillion, twelve billion, two hundred thirty million, three hundred twenty-two thousand, one hundred three".
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