4012314212333 has 6 divisors (see below), whose sum is σ = 4667385920526. Its totient is φ = 3439126467672.

The previous prime is 4012314212327. The next prime is 4012314212341. The reversal of 4012314212333 is 3332124132104.

4012314212333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 3997528381924 + 14785830409 = 1999382^2 + 121597^2 .

It is not a de Polignac number, because 4012314212333 - 2¹⁰ = 4012314211309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4012314212296 and 4012314212305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4012314212323) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 40941981710 + ... + 40941981807.

It is an arithmetic number, because the mean of its divisors is an integer number (777897653421).

Almost surely, 2^{4012314212333} is an apocalyptic number.

It is an amenable number.

4012314212333 is a deficient number, since it is larger than the sum of its proper divisors (655071708193).

4012314212333 is an equidigital number, since it uses as much as digits as its factorization.

4012314212333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81883963531 (or 81883963524 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 4012314212333 its reverse (3332124132104), we get a palindrome (7344438344437).

The spelling of 4012314212333 in words is "four trillion, twelve billion, three hundred fourteen million, two hundred twelve thousand, three hundred thirty-three".