Base | Representation |
---|---|
bin | 111010011000111100011… |
… | …101010101100011010011 |
3 | 112012120222222120111000210 |
4 | 322120330131111203103 |
5 | 1011220112011343000 |
6 | 12311153503415203 |
7 | 562615555236411 |
oct | 72307435254323 |
9 | 15176888514023 |
10 | 4012513777875 |
11 | 1307774470159 |
12 | 54979a8b4503 |
13 | 2314bc52a625 |
14 | dc2c729c2b1 |
15 | 6e5948b6350 |
hex | 3a63c7558d3 |
4012513777875 has 16 divisors (see below), whose sum is σ = 6676822927008. Its totient is φ = 2140007348000.
The previous prime is 4012513777873. The next prime is 4012513777897. The reversal of 4012513777875 is 5787773152104.
It is not a de Polignac number, because 4012513777875 - 21 = 4012513777873 is a prime.
It is a super-2 number, since 2×40125137778752 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4012513777873) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5350017996 + ... + 5350018745.
It is an arithmetic number, because the mean of its divisors is an integer number (417301432938).
Almost surely, 24012513777875 is an apocalyptic number.
4012513777875 is a deficient number, since it is larger than the sum of its proper divisors (2664309149133).
4012513777875 is a wasteful number, since it uses less digits than its factorization.
4012513777875 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10700036759 (or 10700036749 counting only the distinct ones).
The product of its (nonzero) digits is 11524800, while the sum is 57.
The spelling of 4012513777875 in words is "four trillion, twelve billion, five hundred thirteen million, seven hundred seventy-seven thousand, eight hundred seventy-five".
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