Base | Representation |
---|---|
bin | 1001100100010… |
… | …0001011011111 |
3 | 2210111120100201 |
4 | 2121010023133 |
5 | 40233001101 |
6 | 3552004331 |
7 | 665025643 |
oct | 231041337 |
9 | 83446321 |
10 | 40125151 |
11 | 20716690 |
12 | 115306a7 |
13 | 840b7c1 |
14 | 5486c23 |
15 | 37c8e01 |
hex | 26442df |
40125151 has 16 divisors (see below), whose sum is σ = 46599840. Its totient is φ = 34145280.
The previous prime is 40125143. The next prime is 40125167. The reversal of 40125151 is 15152104.
40125151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a 10-Lehmer number, since φ(40125151) divides (40125151-1)10.
It is a cyclic number.
It is not a de Polignac number, because 40125151 - 23 = 40125143 is a prime.
It is a super-2 number, since 2×401251512 = 3220055485545602, which contains 22 as substring.
It is a Duffinian number.
40125151 is a modest number, since divided by 5151 gives 4012 as remainder.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40122151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42355 + ... + 43291.
It is an arithmetic number, because the mean of its divisors is an integer number (2912490).
Almost surely, 240125151 is an apocalyptic number.
40125151 is a deficient number, since it is larger than the sum of its proper divisors (6474689).
40125151 is a wasteful number, since it uses less digits than its factorization.
40125151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1194.
The product of its (nonzero) digits is 200, while the sum is 19.
The square root of 40125151 is about 6334.4416486380. The cubic root of 40125151 is about 342.3514933278.
Adding to 40125151 its reverse (15152104), we get a palindrome (55277255).
It can be divided in two parts, 401 and 25151, that added together give a palindrome (25552).
The spelling of 40125151 in words is "forty million, one hundred twenty-five thousand, one hundred fifty-one".
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