4013001253 has 4 divisors (see below), whose sum is σ = 4015147968. Its totient is φ = 4010854540.

The previous prime is 4013001233. The next prime is 4013001319. The reversal of 4013001253 is 3521003104.

4013001253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4013001253 - 2⁹ = 4013000741 is a prime.

It is a super-2 number, since 2×4013001253² = 32208358113159140018, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4013001253.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4013001233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1070551 + ... + 1074292.

It is an arithmetic number, because the mean of its divisors is an integer number (1003786992).

Almost surely, 2^4013001253 is an apocalyptic number.

It is an amenable number.

4013001253 is a deficient number, since it is larger than the sum of its proper divisors (2146715).

4013001253 is a wasteful number, since it uses less digits than its factorization.

4013001253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2146714.

The product of its (nonzero) digits is 360, while the sum is 19.

The square root of 4013001253 is about 63348.2537486236. The cubic root of 4013001253 is about 1589.1190421991.

Adding to 4013001253 its reverse (3521003104), we get a palindrome (7534004357).

The spelling of 4013001253 in words is "four billion, thirteen million, one thousand, two hundred fifty-three".