4013114353 has 4 divisors (see below), whose sum is σ = 4013246448. Its totient is φ = 4012982260.

The previous prime is 4013114351. The next prime is 4013114419. The reversal of 4013114353 is 3534113104.

4013114353 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 4013114353 - 2¹ = 4013114351 is a prime.

It is a super-2 number, since 2×4013114353² = 32210173620509217218, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4013114351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4998 + ... + 89728.

It is an arithmetic number, because the mean of its divisors is an integer number (1003311612).

Almost surely, 2^4013114353 is an apocalyptic number.

It is an amenable number.

4013114353 is a deficient number, since it is larger than the sum of its proper divisors (132095).

4013114353 is an equidigital number, since it uses as much as digits as its factorization.

4013114353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 132094.

The product of its (nonzero) digits is 2160, while the sum is 25.

The square root of 4013114353 is about 63349.1464267673. The cubic root of 4013114353 is about 1589.1339709821.

Adding to 4013114353 its reverse (3534113104), we get a palindrome (7547227457).

The spelling of 4013114353 in words is "four billion, thirteen million, one hundred fourteen thousand, three hundred fifty-three".