Base | Representation |
---|---|
bin | 10010001111111110001100… |
… | …00011101111000100101111 |
3 | 12021002111122111020011102120 |
4 | 21013333012003233010233 |
5 | 20230002200243031133 |
6 | 221204004141124023 |
7 | 11311245414236214 |
oct | 1107770603570457 |
9 | 167074574204376 |
10 | 40131202314543 |
11 | 1187260254098a |
12 | 4601842559613 |
13 | 1951482594102 |
14 | 9ca509517b0b |
15 | 498d883c6ab3 |
hex | 247fc60ef12f |
40131202314543 has 128 divisors (see below), whose sum is σ = 60279665467392. Its totient is φ = 23617764335616.
The previous prime is 40131202314487. The next prime is 40131202314667. The reversal of 40131202314543 is 34541320213104.
It is not a de Polignac number, because 40131202314543 - 228 = 40130933879087 is a prime.
It is a super-2 number, since 2×401312023145432 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40131202319543) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 7668868455 + ... + 7668873687.
It is an arithmetic number, because the mean of its divisors is an integer number (470934886464).
Almost surely, 240131202314543 is an apocalyptic number.
40131202314543 is a deficient number, since it is larger than the sum of its proper divisors (20148463152849).
40131202314543 is a wasteful number, since it uses less digits than its factorization.
40131202314543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5933.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 40131202314543 its reverse (34541320213104), we get a palindrome (74672522527647).
The spelling of 40131202314543 in words is "forty trillion, one hundred thirty-one billion, two hundred two million, three hundred fourteen thousand, five hundred forty-three".
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