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401312103 = 3251532951
BaseRepresentation
bin10111111010111…
…000100101100111
31000222010202201020
4113322320211213
51310213441403
6103453302223
712642045063
oct2772704547
91028122636
10401312103
111965917a5
12b2494973
13651b08aa
143b426aa3
1525372453
hex17eb8967

401312103 has 8 divisors (see below), whose sum is σ = 537215616. Its totient is φ = 266475000.

The previous prime is 401312089. The next prime is 401312113. The reversal of 401312103 is 301213104.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 401312103 - 28 = 401311847 is a prime.

It is a super-2 number, since 2×4013121032 = 322102808028565218, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (401312113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 265723 + ... + 267228.

It is an arithmetic number, because the mean of its divisors is an integer number (67151952).

Almost surely, 2401312103 is an apocalyptic number.

401312103 is a deficient number, since it is larger than the sum of its proper divisors (135903513).

401312103 is a wasteful number, since it uses less digits than its factorization.

401312103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 533205.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 401312103 is about 20032.7757188064. The cubic root of 401312103 is about 737.6110585600.

Adding to 401312103 its reverse (301213104), we get a palindrome (702525207).

The spelling of 401312103 in words is "four hundred one million, three hundred twelve thousand, one hundred three".

Divisors: 1 3 251 753 532951 1598853 133770701 401312103