Base | Representation |
---|---|
bin | 111010011001100001111… |
… | …011000100111101101111 |
3 | 112012122121210022022011022 |
4 | 322121201323010331233 |
5 | 1011222403414044442 |
6 | 12311340115444355 |
7 | 562640256660500 |
oct | 72314173047557 |
9 | 15178553268138 |
10 | 4013142331247 |
11 | 1307a67250655 |
12 | 5499352b66bb |
13 | 23158c8128ba |
14 | dc346958ba7 |
15 | 6e5ceb743d2 |
hex | 3a661ec4f6f |
4013142331247 has 6 divisors (see below), whose sum is σ = 4668349242528. Its totient is φ = 3439836283884.
The previous prime is 4013142331217. The next prime is 4013142331279. The reversal of 4013142331247 is 7421332413104.
It is not a de Polignac number, because 4013142331247 - 238 = 3738264424303 is a prime.
It is a super-2 number, since 2×40131423312472 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4013142331217) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 40950431903 + ... + 40950432000.
It is an arithmetic number, because the mean of its divisors is an integer number (778058207088).
Almost surely, 24013142331247 is an apocalyptic number.
4013142331247 is a deficient number, since it is larger than the sum of its proper divisors (655206911281).
4013142331247 is an equidigital number, since it uses as much as digits as its factorization.
4013142331247 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81900863917 (or 81900863910 counting only the distinct ones).
The product of its (nonzero) digits is 48384, while the sum is 35.
The spelling of 4013142331247 in words is "four trillion, thirteen billion, one hundred forty-two million, three hundred thirty-one thousand, two hundred forty-seven".
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