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4013202455435 = 51942244236373
BaseRepresentation
bin111010011001100101100…
…000011011101110001011
3112012122202222102221001002
4322121211200123232023
51011223014312033220
612311350104245215
7562641620012615
oct72314540335613
915178688387032
104013202455435
111307a98186868
1254995147080b
1323159c104244
14dc350929db5
156e5d509dc75
hex3a66581bb8b

4013202455435 has 8 divisors (see below), whose sum is σ = 5069308364880. Its totient is φ = 3041585018784.

The previous prime is 4013202455377. The next prime is 4013202455531. The reversal of 4013202455435 is 5345542023104.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4013202455435 - 212 = 4013202451339 is a prime.

It is a super-2 number, since 2×40132024554352 (a number of 26 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21122118092 + ... + 21122118281.

It is an arithmetic number, because the mean of its divisors is an integer number (633663545610).

Almost surely, 24013202455435 is an apocalyptic number.

4013202455435 is a deficient number, since it is larger than the sum of its proper divisors (1056105909445).

4013202455435 is a wasteful number, since it uses less digits than its factorization.

4013202455435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42244236397.

The product of its (nonzero) digits is 288000, while the sum is 38.

Adding to 4013202455435 its reverse (5345542023104), we get a palindrome (9358744478539).

The spelling of 4013202455435 in words is "four trillion, thirteen billion, two hundred two million, four hundred fifty-five thousand, four hundred thirty-five".

Divisors: 1 5 19 95 42244236373 211221181865 802640491087 4013202455435