4013303420131 has 4 divisors (see below), whose sum is σ = 4013805530392. Its totient is φ = 4012801309872.

The previous prime is 4013303420117. The next prime is 4013303420171. The reversal of 4013303420131 is 1310243033104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4013303420131 - 2⁵ = 4013303420099 is a prime.

It is a super-2 number, since 2×4013303420131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4013303420096 and 4013303420105.

It is not an unprimeable number, because it can be changed into a prime (4013303420171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 251043141 + ... + 251059126.

It is an arithmetic number, because the mean of its divisors is an integer number (1003451382598).

Almost surely, 2^{4013303420131} is an apocalyptic number.

4013303420131 is a deficient number, since it is larger than the sum of its proper divisors (502110261).

4013303420131 is an equidigital number, since it uses as much as digits as its factorization.

4013303420131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 502110260.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 4013303420131 its reverse (1310243033104), we get a palindrome (5323546453235).

The spelling of 4013303420131 in words is "four trillion, thirteen billion, three hundred three million, four hundred twenty thousand, one hundred thirty-one".