Base | Representation |
---|---|
bin | 111010011001101100100… |
… | …101011111101111101001 |
3 | 112012200002020220221201011 |
4 | 322121230211133233221 |
5 | 1011223240213120040 |
6 | 12311405550023521 |
7 | 562644561352303 |
oct | 72315445375751 |
9 | 15180066827634 |
10 | 4013321223145 |
11 | 13080492267a3 |
12 | 5499851a7ba1 |
13 | 2315ba8b92b0 |
14 | dc362604973 |
15 | 6e5e070e3ea |
hex | 3a66c95fbe9 |
4013321223145 has 64 divisors (see below), whose sum is σ = 5409073152000. Its totient is φ = 2838175635456.
The previous prime is 4013321223137. The next prime is 4013321223157. The reversal of 4013321223145 is 5413221233104.
It is a cyclic number.
It is not a de Polignac number, because 4013321223145 - 23 = 4013321223137 is a prime.
It is a super-2 number, since 2×40133212231452 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 295808152 + ... + 295821718.
It is an arithmetic number, because the mean of its divisors is an integer number (84516768000).
Almost surely, 24013321223145 is an apocalyptic number.
It is an amenable number.
4013321223145 is a deficient number, since it is larger than the sum of its proper divisors (1395751928855).
4013321223145 is a wasteful number, since it uses less digits than its factorization.
4013321223145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14882.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 4013321223145 its reverse (5413221233104), we get a palindrome (9426542456249).
The spelling of 4013321223145 in words is "four trillion, thirteen billion, three hundred twenty-one million, two hundred twenty-three thousand, one hundred forty-five".
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