Base | Representation |
---|---|
bin | 111010011001110001010… |
… | …111000101111010011011 |
3 | 112012200021211122222022202 |
4 | 322121301113011322123 |
5 | 1011223421220132103 |
6 | 12311421531040415 |
7 | 562646553315020 |
oct | 72316127057233 |
9 | 15180254588282 |
10 | 4013401333403 |
11 | 130808a472820 |
12 | 5499a7ba010b |
13 | 231601387907 |
14 | dc36d0d9547 |
15 | 6e5e7785988 |
hex | 3a6715c5e9b |
4013401333403 has 16 divisors (see below), whose sum is σ = 5005205809920. Its totient is φ = 3126397797600.
The previous prime is 4013401333369. The next prime is 4013401333421. The reversal of 4013401333403 is 3043331043104.
It is not a de Polignac number, because 4013401333403 - 212 = 4013401329307 is a prime.
It is a super-2 number, since 2×40134013334032 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4013401333423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7471388 + ... + 7990521.
It is an arithmetic number, because the mean of its divisors is an integer number (312825363120).
Almost surely, 24013401333403 is an apocalyptic number.
4013401333403 is a deficient number, since it is larger than the sum of its proper divisors (991804476517).
4013401333403 is a wasteful number, since it uses less digits than its factorization.
4013401333403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15465298.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 4013401333403 its reverse (3043331043104), we get a palindrome (7056732376507).
The spelling of 4013401333403 in words is "four trillion, thirteen billion, four hundred one million, three hundred thirty-three thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •