Base | Representation |
---|---|
bin | 111010011001110001010… |
… | …111000101111010101111 |
3 | 112012200021211122222100111 |
4 | 322121301113011322233 |
5 | 1011223421220132143 |
6 | 12311421531040451 |
7 | 562646553315046 |
oct | 72316127057257 |
9 | 15180254588314 |
10 | 4013401333423 |
11 | 130808a472839 |
12 | 5499a7ba0127 |
13 | 231601387921 |
14 | dc36d0d955d |
15 | 6e5e778599d |
hex | 3a6715c5eaf |
4013401333423 has 2 divisors, whose sum is σ = 4013401333424. Its totient is φ = 4013401333422.
The previous prime is 4013401333421. The next prime is 4013401333471. The reversal of 4013401333423 is 3243331043104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4013401333423 - 21 = 4013401333421 is a prime.
It is a super-2 number, since 2×40134013334232 (a number of 26 digits) contains 22 as substring.
Together with 4013401333421, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4013401333421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006700666711 + 2006700666712.
It is an arithmetic number, because the mean of its divisors is an integer number (2006700666712).
Almost surely, 24013401333423 is an apocalyptic number.
4013401333423 is a deficient number, since it is larger than the sum of its proper divisors (1).
4013401333423 is an equidigital number, since it uses as much as digits as its factorization.
4013401333423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 4013401333423 its reverse (3243331043104), we get a palindrome (7256732376527).
The spelling of 4013401333423 in words is "four trillion, thirteen billion, four hundred one million, three hundred thirty-three thousand, four hundred twenty-three".
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