Base | Representation |
---|---|
bin | 10010010000000011011100… |
… | …01010001000111011100011 |
3 | 12021002202221001000202120112 |
4 | 21020001232022020323203 |
5 | 20230023434234044403 |
6 | 221205152045001535 |
7 | 11311405331050421 |
oct | 1110015612107343 |
9 | 167082831022515 |
10 | 40134022565603 |
11 | 1187381a4a028a |
12 | 46022aab532ab |
13 | 1951811961b15 |
14 | 9ca6d5cd0111 |
15 | 498ea0cb19d8 |
hex | 24806e288ee3 |
40134022565603 has 32 divisors (see below), whose sum is σ = 45117305856000. Its totient is φ = 35522919653760.
The previous prime is 40134022565599. The next prime is 40134022565621. The reversal of 40134022565603 is 30656522043104.
It is a cyclic number.
It is not a de Polignac number, because 40134022565603 - 22 = 40134022565599 is a prime.
It is a super-2 number, since 2×401340225656032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40134022565653) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 182810726 + ... + 183030132.
It is an arithmetic number, because the mean of its divisors is an integer number (1409915808000).
Almost surely, 240134022565603 is an apocalyptic number.
40134022565603 is a deficient number, since it is larger than the sum of its proper divisors (4983283290397).
40134022565603 is a wasteful number, since it uses less digits than its factorization.
40134022565603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 230195.
The product of its (nonzero) digits is 518400, while the sum is 41.
The spelling of 40134022565603 in words is "forty trillion, one hundred thirty-four billion, twenty-two million, five hundred sixty-five thousand, six hundred three".
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