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40134103 = 236192819
BaseRepresentation
bin1001100100011…
…0010111010111
32210112000122021
42121012113113
540233242403
63552114011
7665064022
oct231062727
983460567
1040134103
1120722389
1211535907
1384128b9
14548a1b9
1537cb8bd
hex26465d7

40134103 has 8 divisors (see below), whose sum is σ = 41961600. Its totient is φ = 38313528.

The previous prime is 40134079. The next prime is 40134113. The reversal of 40134103 is 30143104.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 40134103 - 29 = 40133591 is a prime.

It is a super-2 number, since 2×401341032 = 3221492447229218, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40134113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12828 + ... + 15646.

It is an arithmetic number, because the mean of its divisors is an integer number (5245200).

Almost surely, 240134103 is an apocalyptic number.

40134103 is a deficient number, since it is larger than the sum of its proper divisors (1827497).

40134103 is a wasteful number, since it uses less digits than its factorization.

40134103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3461.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 40134103 is about 6335.1482224175. The cubic root of 40134103 is about 342.3769511982.

Adding to 40134103 its reverse (30143104), we get a palindrome (70277207).

Subtracting from 40134103 its reverse (30143104), we obtain a palindrome (9990999).

The spelling of 40134103 in words is "forty million, one hundred thirty-four thousand, one hundred three".

Divisors: 1 23 619 2819 14237 64837 1744961 40134103