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401341143105 = 325767123715373
BaseRepresentation
bin1011101011100011100…
…10111101100001000001
31102100221011011111110200
411311301302331201001
523033421313034410
6504212405315413
740665415300140
oct5656162754101
91370834144420
10401341143105
11145231681031
1265948405b69
132bb00450246
14155d4353757
15a68e5143c0
hex5d71cbd841

401341143105 has 96 divisors (see below), whose sum is σ = 807608765184. Its totient is φ = 180574023168.

The previous prime is 401341143103. The next prime is 401341143107. The reversal of 401341143105 is 501341143104.

401341143105 is a `hidden beast` number, since 4 + 0 + 1 + 341 + 1 + 4 + 310 + 5 = 666.

It is an interprime number because it is at equal distance from previous prime (401341143103) and next prime (401341143107).

It is not a de Polignac number, because 401341143105 - 21 = 401341143103 is a prime.

It is a super-2 number, since 2×4013411431052 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (401341143101) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 26099199 + ... + 26114571.

It is an arithmetic number, because the mean of its divisors is an integer number (8412591304).

Almost surely, 2401341143105 is an apocalyptic number.

401341143105 is a gapful number since it is divisible by the number (45) formed by its first and last digit.

It is an amenable number.

401341143105 is an abundant number, since it is smaller than the sum of its proper divisors (406267622079).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

401341143105 is a wasteful number, since it uses less digits than its factorization.

401341143105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16695 (or 16692 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 401341143105 its reverse (501341143104), we get a palindrome (902682286209).

Subtracting 401341143105 from its reverse (501341143104), we obtain a palindrome (99999999999).

It can be divided in two parts, 401341 and 143105, that added together give a triangular number (544446 = T1043).

The spelling of 401341143105 in words is "four hundred one billion, three hundred forty-one million, one hundred forty-three thousand, one hundred five".

Divisors: 1 3 5 7 9 15 21 35 45 63 67 105 201 315 335 469 603 1005 1237 1407 2345 3015 3711 4221 6185 7035 8659 11133 15373 18555 21105 25977 43295 46119 55665 76865 77931 82879 107611 129885 138357 230595 248637 322833 389655 414395 538055 580153 691785 745911 968499 1029991 1243185 1614165 1740459 2900765 3089973 3729555 4842495 5149955 5221377 7209937 8702295 9269919 15449865 19016401 21629811 26106885 36049685 46349595 57049203 64889433 95082005 108149055 133114807 171147609 285246015 324447165 399344421 665574035 855738045 1198033263 1274098867 1996722105 3822296601 5990166315 6370494335 8918692069 11466889803 19111483005 26756076207 44593460345 57334449015 80268228621 133780381035 401341143105