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40134334677847 = 91943671746113
BaseRepresentation
bin10010010000000100000001…
…10000110000001101010111
312021002210201210022201002021
421020002000300300031113
520230030104134142342
6221205243034354011
711311416141004564
oct1110020060601527
9167083653281067
1040134334677847
111187396a697893
12460237758b907
131951861510a17
149ca72553786b
15498ebd3b4567
hex248080c30357

40134334677847 has 4 divisors (see below), whose sum is σ = 40178006424880. Its totient is φ = 40090662930816.

The previous prime is 40134334677817. The next prime is 40134334677893. The reversal of 40134334677847 is 74877643343104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40134334677847 - 27 = 40134334677719 is a prime.

It is a super-2 number, since 2×401343346778472 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40134334677817) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21835872138 + ... + 21835873975.

It is an arithmetic number, because the mean of its divisors is an integer number (10044501606220).

Almost surely, 240134334677847 is an apocalyptic number.

40134334677847 is a deficient number, since it is larger than the sum of its proper divisors (43671747033).

40134334677847 is an equidigital number, since it uses as much as digits as its factorization.

40134334677847 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43671747032.

The product of its (nonzero) digits is 113799168, while the sum is 61.

The spelling of 40134334677847 in words is "forty trillion, one hundred thirty-four billion, three hundred thirty-four million, six hundred seventy-seven thousand, eight hundred forty-seven".

Divisors: 1 919 43671746113 40134334677847