40134356608283 has 4 divisors (see below), whose sum is σ = 45867836123760. Its totient is φ = 34400877092808.

The previous prime is 40134356608279. The next prime is 40134356608331. The reversal of 40134356608283 is 38280665343104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40134356608283 - 2² = 40134356608279 is a prime.

It is a super-2 number, since 2×40134356608283² (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (40134356608183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2866739757728 + ... + 2866739757741.

It is an arithmetic number, because the mean of its divisors is an integer number (11466959030940).

Almost surely, 2^{40134356608283} is an apocalyptic number.

40134356608283 is a deficient number, since it is larger than the sum of its proper divisors (5733479515477).

40134356608283 is an equidigital number, since it uses as much as digits as its factorization.

40134356608283 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5733479515476.

The product of its (nonzero) digits is 9953280, while the sum is 53.

The spelling of 40134356608283 in words is "forty trillion, one hundred thirty-four billion, three hundred fifty-six million, six hundred eight thousand, two hundred eighty-three".