40134416553353 has 4 divisors (see below), whose sum is σ = 40792357808388. Its totient is φ = 39476475298320.

The previous prime is 40134416553331. The next prime is 40134416553359. The reversal of 40134416553353 is 35335561443104.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4821502507264 + 35312914046089 = 2195792^2 + 5942467^2 .

It is a cyclic number.

It is not a de Polignac number, because 40134416553353 - 2¹² = 40134416549257 is a prime.

It is a super-2 number, since 2×40134416553353² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 40134416553298 and 40134416553307.

It is not an unprimeable number, because it can be changed into a prime (40134416553359) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 328970627426 + ... + 328970627547.

It is an arithmetic number, because the mean of its divisors is an integer number (10198089452097).

Almost surely, 2^{40134416553353} is an apocalyptic number.

It is an amenable number.

40134416553353 is a deficient number, since it is larger than the sum of its proper divisors (657941255035).

40134416553353 is an equidigital number, since it uses as much as digits as its factorization.

40134416553353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 657941255034.

The product of its (nonzero) digits is 3888000, while the sum is 47.

Adding to 40134416553353 its reverse (35335561443104), we get a palindrome (75469977996457).

The spelling of 40134416553353 in words is "forty trillion, one hundred thirty-four billion, four hundred sixteen million, five hundred fifty-three thousand, three hundred fifty-three".