4013444140035 has 40 divisors (see below), whose sum is σ = 7063618213200. Its totient is φ = 1945912203840.

The previous prime is 4013444140003. The next prime is 4013444140081. The reversal of 4013444140035 is 5300414443104.

4013444140035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 4013444140035 - 2⁵ = 4013444140003 is a prime.

It is a super-2 number, since 2×4013444140035² (a number of 26 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (33).

It is a junction number, because it is equal to n+sod(n) for n = 4013444139978 and 4013444140005.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 8917840 + ... + 9357069.

It is an arithmetic number, because the mean of its divisors is an integer number (176590455330).

Almost surely, 2^{4013444140035} is an apocalyptic number.

4013444140035 is a deficient number, since it is larger than the sum of its proper divisors (3050174073165).

4013444140035 is an equidigital number, since it uses as much as digits as its factorization.

4013444140035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18274961 (or 18274928 counting only the distinct ones).

The product of its (nonzero) digits is 46080, while the sum is 33.

Adding to 4013444140035 its reverse (5300414443104), we get a palindrome (9313858583139).

The spelling of 4013444140035 in words is "four trillion, thirteen billion, four hundred forty-four million, one hundred forty thousand, thirty-five".