Base | Representation |
---|---|
bin | 111010011001110011111… |
… | …010100111111101000111 |
3 | 112012200101211022221102002 |
4 | 322121303322213331013 |
5 | 1011224013203433221 |
6 | 12311430101535515 |
7 | 562650613562165 |
oct | 72316372477507 |
9 | 15180354287362 |
10 | 4013444202311 |
11 | 1308101692875 |
12 | 5499ba41459b |
13 | 23160a21722b |
14 | dc374a98235 |
15 | 6e5eb40280b |
hex | 3a673ea7f47 |
4013444202311 has 4 divisors (see below), whose sum is σ = 4079238369624. Its totient is φ = 3947650035000.
The previous prime is 4013444202259. The next prime is 4013444202329. The reversal of 4013444202311 is 1132024443104.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4013444202311 is a prime.
It is a super-2 number, since 2×40134442023112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4013444202811) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32897083565 + ... + 32897083686.
It is an arithmetic number, because the mean of its divisors is an integer number (1019809592406).
Almost surely, 24013444202311 is an apocalyptic number.
4013444202311 is a deficient number, since it is larger than the sum of its proper divisors (65794167313).
4013444202311 is an equidigital number, since it uses as much as digits as its factorization.
4013444202311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65794167312.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 4013444202311 its reverse (1132024443104), we get a palindrome (5145468645415).
The spelling of 4013444202311 in words is "four trillion, thirteen billion, four hundred forty-four million, two hundred two thousand, three hundred eleven".
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