Base | Representation |
---|---|
bin | 1011101011100100101… |
… | …00111010101011000001 |
3 | 1102100221202220201200112 |
4 | 11311302110322223001 |
5 | 23033431102404403 |
6 | 504213324201105 |
7 | 40665554042246 |
oct | 5656224725301 |
9 | 1370852821615 |
10 | 401350044353 |
11 | 145236700735 |
12 | 6594b399195 |
13 | 2bb0224895b |
14 | 155d55cd5cd |
15 | a6901c19d8 |
hex | 5d7253aac1 |
401350044353 has 4 divisors (see below), whose sum is σ = 401422929840. Its totient is φ = 401277158868.
The previous prime is 401350044301. The next prime is 401350044377. The reversal of 401350044353 is 353440053104.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 401350044353 - 232 = 397055077057 is a prime.
It is a super-2 number, since 2×4013500443532 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (401350044383) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36434483 + ... + 36445496.
It is an arithmetic number, because the mean of its divisors is an integer number (100355732460).
Almost surely, 2401350044353 is an apocalyptic number.
It is an amenable number.
401350044353 is a deficient number, since it is larger than the sum of its proper divisors (72885487).
401350044353 is an equidigital number, since it uses as much as digits as its factorization.
401350044353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72885486.
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 401350044353 its reverse (353440053104), we get a palindrome (754790097457).
The spelling of 401350044353 in words is "four hundred one billion, three hundred fifty million, forty-four thousand, three hundred fifty-three".
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