Base | Representation |
---|---|
bin | 111010011001111010011… |
… | …100101011110110110001 |
3 | 112012200200110112210121100 |
4 | 322121322130223312301 |
5 | 1011224224232410411 |
6 | 12311445014515013 |
7 | 562653414234660 |
oct | 72317234536661 |
9 | 15180613483540 |
10 | 4013553794481 |
11 | 1308158536010 |
12 | 549a2b065a69 |
13 | 231626b38a7a |
14 | dc385464dd7 |
15 | 6e605d4e456 |
hex | 3a67a72bdb1 |
4013553794481 has 96 divisors (see below), whose sum is σ = 7301619127296. Its totient is φ = 2063702160000.
The previous prime is 4013553794417. The next prime is 4013553794507. The reversal of 4013553794481 is 1844973553104.
4013553794481 is a `hidden beast` number, since 4 + 0 + 1 + 3 + 553 + 7 + 9 + 4 + 4 + 81 = 666.
It is not a de Polignac number, because 4013553794481 - 26 = 4013553794417 is a prime.
It is a super-2 number, since 2×40135537944812 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4013553794881) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 318251866 + ... + 318264476.
It is an arithmetic number, because the mean of its divisors is an integer number (76058532576).
Almost surely, 24013553794481 is an apocalyptic number.
It is an amenable number.
4013553794481 is a deficient number, since it is larger than the sum of its proper divisors (3288065332815).
4013553794481 is a wasteful number, since it uses less digits than its factorization.
4013553794481 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17283 (or 17280 counting only the distinct ones).
The product of its (nonzero) digits is 7257600, while the sum is 54.
The spelling of 4013553794481 in words is "four trillion, thirteen billion, five hundred fifty-three million, seven hundred ninety-four thousand, four hundred eighty-one".
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