Base | Representation |
---|---|
bin | 100101011000010100… |
… | …010000100011000111 |
3 | 10211121011201221200011 |
4 | 211120110100203013 |
5 | 1124144410130320 |
6 | 30234410331051 |
7 | 2620421603326 |
oct | 453024204307 |
9 | 124534657604 |
10 | 40136411335 |
11 | 16026a59989 |
12 | 7941729a87 |
13 | 3a28404327 |
14 | 1d2a75a0bd |
15 | 109d98005a |
hex | 9585108c7 |
40136411335 has 16 divisors (see below), whose sum is σ = 48345403392. Its totient is φ = 31988106400.
The previous prime is 40136411333. The next prime is 40136411351. The reversal of 40136411335 is 53311463104.
It is not a de Polignac number, because 40136411335 - 21 = 40136411333 is a prime.
It is a super-2 number, since 2×401364113352 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 40136411297 and 40136411306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40136411333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3276492 + ... + 3288718.
It is an arithmetic number, because the mean of its divisors is an integer number (3021587712).
Almost surely, 240136411335 is an apocalyptic number.
40136411335 is a deficient number, since it is larger than the sum of its proper divisors (8208992057).
40136411335 is a wasteful number, since it uses less digits than its factorization.
40136411335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14654.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 40136411335 its reverse (53311463104), we get a palindrome (93447874439).
The spelling of 40136411335 in words is "forty billion, one hundred thirty-six million, four hundred eleven thousand, three hundred thirty-five".
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