40140202213131 has 4 divisors (see below), whose sum is σ = 53520269617512. Its totient is φ = 26760134808752.

The previous prime is 40140202213091. The next prime is 40140202213141. The reversal of 40140202213131 is 13131220204104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40140202213131 - 2¹³ = 40140202204939 is a prime.

It is a super-2 number, since 2×40140202213131² (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (40140202213141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6690033702186 + ... + 6690033702191.

It is an arithmetic number, because the mean of its divisors is an integer number (13380067404378).

Almost surely, 2^{40140202213131} is an apocalyptic number.

40140202213131 is a deficient number, since it is larger than the sum of its proper divisors (13380067404381).

40140202213131 is a wasteful number, since it uses less digits than its factorization.

40140202213131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13380067404380.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 40140202213131 its reverse (13131220204104), we get a palindrome (53271422417235).

The spelling of 40140202213131 in words is "forty trillion, one hundred forty billion, two hundred two million, two hundred thirteen thousand, one hundred thirty-one".