4014054403 has 4 divisors (see below), whose sum is σ = 4015265688. Its totient is φ = 4012843120.

The previous prime is 4014054397. The next prime is 4014054449. The reversal of 4014054403 is 3044504104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4014054403 is a prime.

It is a super-2 number, since 2×4014054403² = 32225265500487372818, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4014054493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 600658 + ... + 607303.

It is an arithmetic number, because the mean of its divisors is an integer number (1003816422).

Almost surely, 2^4014054403 is an apocalyptic number.

4014054403 is a deficient number, since it is larger than the sum of its proper divisors (1211285).

4014054403 is a wasteful number, since it uses less digits than its factorization.

4014054403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1211284.

The product of its (nonzero) digits is 3840, while the sum is 25.

The square root of 4014054403 is about 63356.5655871592. The cubic root of 4014054403 is about 1589.2580432636.

Adding to 4014054403 its reverse (3044504104), we get a palindrome (7058558507).

The spelling of 4014054403 in words is "four billion, fourteen million, fifty-four thousand, four hundred three".