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40155412513 = 1729471733003
BaseRepresentation
bin100101011001011100…
…101111100000100001
310211122111111022101111
4211121130233200201
51124214241200023
630240325503321
72621042242336
oct453134574041
9124574438344
1040155412513
1116036757837
127947b71b41
133a2c327c28
141d2d0a498d
1510a048500d
hex95972f821

40155412513 has 16 divisors (see below), whose sum is σ = 44919463680. Its totient is φ = 35713705216.

The previous prime is 40155412489. The next prime is 40155412543. The reversal of 40155412513 is 31521455104.

It is a cyclic number.

It is not a de Polignac number, because 40155412513 - 25 = 40155412481 is a prime.

It is a super-2 number, since 2×401554125132 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (40155412543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 843331 + ... + 889672.

It is an arithmetic number, because the mean of its divisors is an integer number (2807466480).

Almost surely, 240155412513 is an apocalyptic number.

It is an amenable number.

40155412513 is a deficient number, since it is larger than the sum of its proper divisors (4764051167).

40155412513 is a wasteful number, since it uses less digits than its factorization.

40155412513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1733096.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 40155412513 its reverse (31521455104), we get a palindrome (71676867617).

The spelling of 40155412513 in words is "forty billion, one hundred fifty-five million, four hundred twelve thousand, five hundred thirteen".

Divisors: 1 17 29 47 493 799 1363 23171 1733003 29461051 50257087 81451141 854370479 1384669397 2362083089 40155412513