Base | Representation |
---|---|
bin | 111010100000000001011… |
… | …101111101101101111011 |
3 | 112020022121122202211220220 |
4 | 322200001131331231323 |
5 | 1011331143142134433 |
6 | 12314452003151123 |
7 | 563305113240345 |
oct | 72400135755573 |
9 | 15208548684826 |
10 | 4020114021243 |
11 | 130aa14619521 |
12 | 54b1600754a3 |
13 | 232130cb5b58 |
14 | dc808826295 |
15 | 6e88bc4a2b3 |
hex | 3a80177db7b |
4020114021243 has 16 divisors (see below), whose sum is σ = 5624103803136. Its totient is φ = 2549387697120.
The previous prime is 4020114021227. The next prime is 4020114021257. The reversal of 4020114021243 is 3421204110204.
It is not a de Polignac number, because 4020114021243 - 24 = 4020114021227 is a prime.
It is a super-3 number, since 3×40201140212433 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (4020114021743) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 160933705 + ... + 160958682.
It is an arithmetic number, because the mean of its divisors is an integer number (351506487696).
Almost surely, 24020114021243 is an apocalyptic number.
4020114021243 is a deficient number, since it is larger than the sum of its proper divisors (1603989781893).
4020114021243 is a wasteful number, since it uses less digits than its factorization.
4020114021243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 321892594.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 4020114021243 its reverse (3421204110204), we get a palindrome (7441318131447).
The spelling of 4020114021243 in words is "four trillion, twenty billion, one hundred fourteen million, twenty-one thousand, two hundred forty-three".
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