Base | Representation |
---|---|
bin | 101101101101000001001001… |
… | …1111000101101001001010011 |
3 | 1221201101220202001220011021220 |
4 | 1123122002103320231021103 |
5 | 410143023342011140311 |
6 | 3543001255150420123 |
7 | 150451236516003261 |
oct | 13332022370551123 |
9 | 1851356661804256 |
10 | 402011420021331 |
11 | 1071030a420553a |
12 | 3910860b201643 |
13 | 1434168ba3b0a3 |
14 | 713b656aa1431 |
15 | 317238d9b6206 |
hex | 16da093e2d253 |
402011420021331 has 16 divisors (see below), whose sum is σ = 539928918617088. Its totient is φ = 266050775880000.
The previous prime is 402011420021273. The next prime is 402011420021377. The reversal of 402011420021331 is 133120024110204.
It is not a de Polignac number, because 402011420021331 - 210 = 402011420020307 is a prime.
It is a super-2 number, since 2×4020114200213312 (a number of 30 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (402011420026331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 277009926 + ... + 278457396.
It is an arithmetic number, because the mean of its divisors is an integer number (33745557413568).
Almost surely, 2402011420021331 is an apocalyptic number.
402011420021331 is a deficient number, since it is larger than the sum of its proper divisors (137917498595757).
402011420021331 is a wasteful number, since it uses less digits than its factorization.
402011420021331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2123362.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 402011420021331 its reverse (133120024110204), we get a palindrome (535131444131535).
The spelling of 402011420021331 in words is "four hundred two trillion, eleven billion, four hundred twenty million, twenty-one thousand, three hundred thirty-one".
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